Papa Legba
Special user
home-an unremarkable spiral arm of an insignificant galaxy
750 Posts
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Posted: Dec 7, 2023 10:40 pm
0
I am trying to work on an effect in which the volunteer may lie. For example, suppose we have 8 options requiring 3 cards. Instead of answering truthfully the volunteer lies. Let's say the target number is 6, if they lie the outcome of the answers is 9 (an out of range and thus impossible number) simply subtract from 15 to get 6. My problem is this breaks down for the numbers 7 and 8. You will not know if they lied or not. Anyone have an inkling how to solve this?
Use the FORCE Luke.
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saxonia
Regular user
168 Posts
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Posted: Dec 8, 2023 10:57 pm
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I am afraid your approach cannot be understood without more details and one or two examples.
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Papa Legba
Special user
home-an unremarkable spiral arm of an insignificant galaxy
750 Posts
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Posted: Dec 11, 2023 07:37 pm
0
Thanks saxonia, I have worked it out, not as difficult as I thought. It's basically the old binary 'age'/'computer' cards but the volunteer is able to lie.
Use the FORCE Luke.
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FreddieLeeFroth
New user
50 Posts
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Posted: Dec 15, 2023 01:41 pm
0
Are you aware of the work of Leo Boudreau? That might be helpful to you in finding methods for this type of effect.
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Papa Legba
Special user
home-an unremarkable spiral arm of an insignificant galaxy
750 Posts
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Posted: Dec 17, 2023 05:10 pm
1
Quote: On Dec 15, 2023, FreddieLeeFroth wrote:
Are you aware of the work of Leo Boudreau? That might be helpful to you in finding methods for this type of effect.
Thanks Freddie, yes I am aware of Leo's work and I have now resolved my difficulty (much easier than I thought actually).
Also I did not realise that 'Magical Equations' was an open forum, will have to take care what I ask about in future.
Use the FORCE Luke.
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Good to here.